please answer it its really important iam saying not for free points even armys also i will report
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Answer:
2
Please see the attachment
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2
y=log
x
a+log
a
x
=
lnx
lna
+
lna
lnx
=
lnx
lna
+
lnx
lna
1
=log
x
a+
log
x
a
1
Applying A.M≥G.M
Hence
2
log
x
a+
log
x
a
1 ≥
log
x
a.
log
x
a
1
log x
a+ log x
a
1 ≥2
y≥2.
Hence the minimum value of the function is 2.
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