Math, asked by donaina506, 5 hours ago

Please answer it. PLEASE ​

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Answered by AestheticDude
11

Answer :-

   \rm{ \tt  \leadsto}  \bf\dfrac{5 \times  {t}^{ 4} }{8  }

Step-by-step-Explaination :-

  \rm\dfrac{25 \times  {5}^{2} \times  {t}^{8}  }{ {10}^{3} \times  {t}^{4}  }

  {\tt  \leadsto}\rm\dfrac{25 \times  25 \times  {t}^{8}  }{ ({2 \times 5)}^{3} \times  {t}^{4}  }

  {\tt  \leadsto}\rm\dfrac{25 \times  25 \times  {t}^{8}  }{ {2 }^{3} \times  {5}^{3}  \times  {t}^{4}  }

  {\tt  \leadsto}\rm\dfrac{ \cancel{25} \times  \cancel{ 25} \times  {t}^{8}  }{ 8\times   \cancel{125}  \times  {t}^{4}  }

  \rm{ \tt  \leadsto} \dfrac{5 \times  {t}^{8} }{8 \times  {t}^{4} }

  \rm{ \tt  \leadsto} \dfrac{5 \times  {t}^{8 - 4} }{8  }

  \rm{ \tt  \leadsto} \dfrac{5 \times  {t}^{ 4} }{8  }

Answered by 555sskal7
0

Step-by-step explanation:

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