Question

Q4. Write the expression for the following (i) number of Wheels in ‘c’ cars. (ii) Weight of Satya increases x kg every year. If her present weight is 50 kg What will be her weight after 5 years? (iii) y is multiplied by 5, then the resultant is subtracted from 10. (iv) one of the angles of an equilateral triangle is ‘n’, what will be the sum of all the angles?​

Answer 1

Mass of car m=1800kg

Distance between front and back axles d=1.8m

Distance between center of gravity and front axle=1.05m

Let R

b

and R

f

be the forces exerted by the level ground on the back and front wheels respectively.

At translational equilibrium:

R

f

+R

b

=mg=17640 N.(i)

For rotational equilibrium, on taking the torque about the C.G., we have:

R

f

(1.05)=R

b

(1.8−1.05)

⟹R

b

=1.4R

f(ii)

Solving (i) and (ii) gives

R

f

=7350 N

R

b

=10290 N

The force exerted on each front wheel =7350/2=3675 N

The force exerted on each back wheel =10290/2=5145N

Answer 2

Step-by-step explanation:

(i) Number of wheels in ‘c’ cars.

I guess the question is incomplete. But if it is complete..

Assume that the number of wheels in cars i.e. 'c' is n.

So, the required expression of the given statement is nc.

(ii) Weight of Satya increases x kg every year. If her present weight is 50 kg What will be her weight after 5 years?

Assume that the weight of Satya is 's' which increases 'x' every year. Also given that her present weight is 50 kg.

Means s = 50 kg and it increases x every year. So,

→ 50 + x

After 5 years her weight = 50 + x + 5

= 55 + x

Therefore, the weight of Satya after 5 years is (55 + x).

(iii) y is multiplied by 5, then the resultant is subtracted from 10.

Just write statement by statement; y is multiplied by 5

→ (y × 5) or (5y)

then the resultant i.e. (5y) from 10

→ 10 - 5y

Hence, the required expression is (10 - 5y).

(iv) one of the angles of an equilateral triangle is ‘n’, what will be the sum of all the angles?

Sum of all angles of equilateral triangle is 180° and one of the angle is 'n'.

Assume the rest two angles be 'a' and 'b'.

So,

→ a + b + n = 180°

Hence, the required expression is (a + b + n = 180°).