Question

Please answer it's from laws of indices​

Answer 1

Answer:

3y^2 / x

2b root (b) / root (a)

Step-by-step explanation:

NOTE

• a^1/2 = square root a
• a^-1 = 1/a
• a^m / a^n = a^ m-n if m>n
• a^m / a^n = 1/a^n-m if n>m

(9xy^6 / x^3y^2 ) ^ 1/2

=> ( 9 y^6-2 / x^3-1 ) ^1/2

=> ( 9y^4 / x^2 ) ^1/2

=> square root ( 9y^4 / x^2 )

=> 3y^2 / x

( 3a^2b / 12ab^4 )^ -1/2

=> ( 3a^2-1 / 12 b^4-1 ) ^-1/2

=> ( 3a / 12b^3 ) ^-1/2

=> ( a / 4b^3 ) ^ -1/2

=> ( 4b^3 / a ) ^1/2

=> square root ( 4b^3 / a )

=> 2b root (b)

2b root (b) root (a)