Question

please answer it... the one who gives the step by step solution will get the brainliest 6. In a fraction, if numerator is increased by 2 and
denominator is increased by 3, it becomes
3
4.
and
if numerator is decreased by 3 and denominator
is decreased by 6, it becomes
4
3
.. Find the sum of
the numerator and denominator.
(a) 16
(b) 18
(c) 20
(d) 14​

Answer 1

Hola mate! Refer to the image!

Answer 2

Answer:

$\frac{7}{9}$

Step-by-step explanation:

let numerator = x

denominator = y

Given:

$\frac{x+2}{y+3} =\frac{3}{4}$

on simplifying we get(cross multiplying) =

4x+8=3y+9

4x - 3y = 1 --------(1)

also,

$\frac{x-3}{y-6} =\frac{4}{3}$

on cross multiplying we get,

3x - 9 = 4y - 24

3x - 4y = -15 --------(2)

comparing (1) and (2) we get,

4x - 3y = 1

3x - 4y = -15

solving using substitution method we get,

x = 7

and y =  9

thus the fraction is equal to:

$\frac{7}{9}$

Therefore sum = 7+9 = 16

Mark as brainliest if you are satisfied with my answer