Question

please answer it urgently please the perimeter of an isoscles triangle is 42 cm and its base is (3/2) times each of the equal sides. find the length of each side of the triangle, area of the triangle and the height of the triangle.

Answer 1

let x is one side of triangle
42=x+x+3/2x
42=2x+3/2x
42=2+3/2x
42=7/2x
42×2/7=x
x=2×6
x=12
now12 is one side
2 side is 24
then base = 42-24 =18
half of base is 9
by using Pythagoras
12^2=9^2+height^2
height^2=114-81
height ^2=33
height=√33

Answer 2

PERIMETER OF TRIANGLE = 3xSIDE
42 = 3xSIDE
42/3 = SIDE
14 = SIDE
BASE OF THE TRIANGLE = 3/2 x 14
= 21
SIDES OF TRIANGLE = 14 AND 14 cm

BASE OF THE TRIANGLE= 21 cm

LENGTH OF EACH SIDES OF THE TRIANGLE = 14 , 14 AND 21

BY PHYTHAGORAS THEOREM
H^2=P^2+B^2
14^2= P^2 + 11^2
196 = P^2 + 121
196-121=P^2
144=P^2
12= P

AREA OF THE TRIANGLE =1/2 BASE x HEIGHT
AREA OF THE TRIANGLE= 1/2 x 14 x 12
= 84



HOPE THIS WILL HELP U