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In ∆DOA and ∆BOC
angle DAO = angle CBO = 90°
angle DOA = angle BOC (vertical opposite angle)
AD=BC (given)
∆DOA congurent to ∆BOC
so,DO=CO (c.p.c.t.c) and BO=AO (c.p.c.t.c)
so, it can be said that CD bisect AB
(hence proved)
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