Math, asked by zameh2018, 1 year ago

Please answer me fast

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Answered by Anonymous
2

Answer:

1, of course

Step-by-step explanation:

Let's solve the exponents...

We know, x^a * x^b = x^(a+b)

(a-b)(a+b) = a^2 - b^2

(b-c)(b+c) = b^2 - c^2

(c-a)(c+a) = c^2 - a^2

Thus, x^(a^2-b^2+b^2-c^2+c^2-a^2)

= x^0 = 1.....

Comment in case of any query....

Answered by meh76612001
2

Answer:

Step-by-step explanation:

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