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1, of course
Step-by-step explanation:
Let's solve the exponents...
We know, x^a * x^b = x^(a+b)
(a-b)(a+b) = a^2 - b^2
(b-c)(b+c) = b^2 - c^2
(c-a)(c+a) = c^2 - a^2
Thus, x^(a^2-b^2+b^2-c^2+c^2-a^2)
= x^0 = 1.....
Comment in case of any query....
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