Question

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Answer 1

Step-by-step explanation:

GIVEN:

∆ABC & ∆BDC are two isosceles triangle in which AB = AC & BD = DC

REQUIRED TO PROOF:

<ACD = <ABD

PROOF:

In ∆ABC,

AB = AC. [GIVEN]

Therefore,

<ACB = <ABC ------------(i) [OPPOSITE SIDES OF THE EQUAL ANGLES ARE EQUAL]

Again,

In ∆ BCD,

BD = BC. [GIVEN]

Therefore,

<BCD = <DBC ------------ (ii). [OPPOSITE SIDES OF THE EQUAL ANGLES ARE EQUAL]

Adding equation (i) and (ii)

We get,

<ACB + <BCD = <ABC + <DBC

→ <ACD = <ABD. (HENCE PROVED)

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