please answer me fast
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Using formula (a+b)^3 and (a-b)^3
=(a^3 + b^3 +3a^2b +3ab^2 ) (a^3 + b^3- 3a^2b -3ab^2)
=2a^3 + 2b^3 +3a^2b -3a^2b + 3ab^2 -3ab^2 ( Since 3a^2b and -3a^2b are opposite signs they got cancelled same is the case for 3ab^2-3ab^2)
So finally we get our answer ^_^
2a^3 +2b^3
=2 (a^3 +b^3)
Hope it helps uh a lot ❤
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