Question

Please answer me fast:​

Answer 1

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

1. X^2+Y^2+Z^2+2XYZ

WE HAVE GIVEN

X=4 , Y=3 AND Z=-2

SO , NOW

$(4)^{2} +(3)^{2} +(-2)^{2} +2(4)(3)(-2)$

16+9+4-48

-19 -------- ANSWER

TRY TO DO 2ND ONE BY YOURSELF

HOPE YOU UNDERSTAND

Answer 2

Given :

• Value of x = 4
• Value of y = 3
• Value of z = -2

To find :

• Value of

1. x² + y² + z² + 2xyz
2. x³ + y³ + z³ - 3xyz

__________...

According to the question,

→ x² + y² + z² + 2xyz

→ 4² + 3² + (-2)² + 2 × 4 × 3 × (-2)

→ 16 + 9 + 4 + (-48)

→ 25 + 4 - 48

→ -19 ........(Answer)

___________.....

→ x³ + y³ + z³ - 3xyz

→ 4³ + 3³ + (-2)³ - 3 × 4 × 3 × (-2)

→ 64 + 27 + (-8) - (-72)

→ 91 - 8 + 72

→ 83 + 72

→ 155 ........(Answer)