Question

please answer me fast ​

Answer 1

Answer:

1)8

2)<

3)7

4)37/4

5)3

1)0

2)-11

3)18/49

4)0.45...

5)2.1022

1)

Answer 2

Q.1 [ A ] M.C.Q.

1) The addictive inverse of ( -8 ) is $\tt\:8$

➻ Addictive inverse of a given number is that number which we add to the given number to make it's sum 0.

• Here, ( -8 ) + 8 = 0 $\sf\color{red}{⋆}$

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2) -19 + ( -11 ) $\tt\:<$ 19 - ( -11 )

Taking LHS and Solving

$\tt\to~-19+(-11)$

$\tt\to~-19-11$

$\tt\to~-30$

Taking RHS and Solving

$\tt\to~-19-(-11)$

$\tt\to~-19+11$

$\tt\to~-8$

So clearly ( -30 ) < ( -8 ) $\sf\color{red}{⋆}$

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3) In 260.67 , the place value of 7 is $\tt~700$ $\sf\color{red}{⋆}$

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4) The reciprocal of $\tt\:9\frac{1}{4}$ is $\sf\:\frac{4}{37}$

➻ Solving

$\tt\:9\frac{1}{4}$

$\tt\to\:\frac{37}{4}$

So reciprocal is 4/37. $\sf\color{red}{⋆}$

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5) The number of negative integers between -5 and 5 are $\tt\:4$

➻ Between -5 and 5 there are 4 negative number i.e., -4 , -3 , -2 and -1. $\sf\color{red}{⋆}$

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[ B ] Fill in the blanks :

1) The product of -ve integer and zero is always zero .

➻ Any number multiplied with 0 gives 0.$\sf\color{red}{⋆}$

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2) $\tt\:x= 11$ × ( -12 ) = 132

➻ Solving

$\tt\:x \times (-12) = 132$

$\tt\to\:-12x= 132$

$\tt\to\:x= \frac{132}{-12}$

$\tt\to\:x= \cancel{\frac{132}{-12}}$

$\tt\to\:x= 11$ $\sf\color{red}{⋆}$

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3) $\sf\:\frac{3}{7} \times {6}{7}$=$\tt~\frac{18}{49}$

➻ Solving

$\tt\:\frac{3}{7} \times {6}{7}$

$\tt\to\:\frac{3 \times 6}{7 \times 7}$

$\tt\to\:\frac{18}{49}$ $\sf\color{red}{⋆}$

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4) The lowest form of $\sf\:\frac{40}{88}$ is $\tt\:\frac{5}{22}$

➻ Solving

$\sf\:\frac{40}{88}$

$\sf\to\:\cancel{\frac{40}{88}}$

$\sf\to\:\cancel{\frac{10}{44}}$

$\sf\to\:\frac{5}{22}$ $\sf\color{red}{⋆}$

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5) 21.022 ÷ 10 = $\tt\:2.1022$

➻ Solving

$\sf\:21.022 \div 10$

$\sf\to\:\frac{21022}{1000} \div 10$

$\sf\to\:\frac{21022}{1000} \times \frac{1}{10}$

$\sf\to\:\frac{21022}{10000}$

$\sf\to\:2.1022$ $\sf\color{red}{⋆}$

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Q.2 Solve the following :

1) Find the product ‎using suitable identity : 26 × ( -48 ) + ( -48 ) × 36 .

➻ Solving

26 × ( -48 ) + ( -48 ) × 36

➝ ( -1248 ) + ( -1728 )

➝ -1248 - 1728

➝ -2976 $\sf\color{red}{⋆}$

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2) Verify the following :

18 × [ 7 + ( -3 ) ] = [ 18 × 7 ] + [ 18 × ( -3 ) ]

➻ Solving

Taking LHS,

18 × [ 7 + ( -3 ) ]

➝ 18 × [ 7 - 3 ]

➝ 18 × 4

➝ 72

Taking RHS,

[ 18 × 7 ] + [ 18 × ( -3 ) ]

➝ 126 + [ -54 ]

➝ 126 - 54

➝ 72

So LHS = RHS = 72 .

Hence Verified !~ $\sf\color{red}{⋆}$

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3) Convert the following :

a) 73 rupees 78 paise in to rupees .

Converting 78 paise into rupees -

➻ 100p = 1 rs

➻ 1p = 1/100 rs

➻ 78p = 78/ 100 rs = Rs 0.77

$\sf\therefore\:Total~Amount~~$

$\sf\to\:Rs~(73+78)~=~Rs~151$ $\sf\color{red}{⋆}$

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b) 3470 g into kg

For converting g into kg we need to divide by 1000.

$\sf\therefore\:3470~g~into~kg$

$\sf\to\:\frac{3470}{1000}~kg$

$\sf\to\:\frac{347\cancel{0}}{100\cancel{0}}~kg$

$\sf\to\:\frac{347}{100}~kg$

$\sf\to\:3.47~kg$ $\sf\color{red}{⋆}$

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4) Find : 121.48 × 1.1

➻ Solving

$\tt\:121.48 \times 1.1$

$\tt\to\:\frac{12148}{100} \times \frac{11}{10}$

$\tt\to\:\frac{133628}{1000}$

$\tt\to\:133.628$ $\sf\color{red}{⋆}$

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