Physics, asked by Anonymous, 1 month ago

please answer me fast guys​

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Answered by bhaleuday30
3

5 bulbs of 40W each used for 5hr : 5*40w*5/1000

therefore 5*40*5/1000= 1000/1000=1kwh

electric press for 4 hr and 500w : 4*500*1/1000=2kwh

total energy for 30 days : 1*30 =30 units for bulbs

total energy for electric press for 30 days :2*30=60 units

total energy = 30+60=90units

Answered by Vishwash8
47

Answer:

90 kwh

Explanation:

Given,

  • 5 tube lights of 40 watts are used for 5 hours per day
  • An electric press is used of 500 watts is used for 4 hours per day

Energy consumed by the bulbs in one day-

=> (5×40×5)/1000( divided by 1000 to convert the energy consumed in kwh)

=> (25×40)/1000

=> 1000/1000

=> 1 kwh

Energy consumed by the electric press in one day-

=> 1×500×4/1000 (divided by 1000 to convert the energy consumed in kwh)

=> 2000/1000

=> 2 kwh

Total energy consumed in one day-

=> energy consumed by the bulbs in one day+ energy consumed by the press in one day

=>1+2

=> 3kwh

Total energy consumed by the press and the bulbs in a month of 30 days-

=> Total energy consumed in one day×30

=> 3×30

=> 90 kwh

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