English, asked by Anonymous, 4 months ago

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Answered by saritabakshig90
12

Answer:

Since, Factors of 5 and 2 both are not in group of three. Therefore, the number must be multiplied by2×5×2 = 20 to make it a perfectcube. Hence he needs 20cuboids.

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Answered by zara208
0

Answer:

Here cuboids are joined to form a cube

so,

volume of cuboid* number of cuboid =volume of cube

VOLUME OF CUBOID

sides are 5,2,5 cm

l=5cm

b=2cm

h=5cm

5*2*5

VOLUME OF CUBE

let side of cube =a

volume=side^3

=a^3

now ,

volume of cuboid*number of cuboids =volume of cuboid

5*2*5*number of cuboids=a^3

a^3=5*2*5*number of cuboids

since on the left we have a cube ,

we should have cube on the right as well

to form cube on the right

we multiply

5*2*5

thus in a^3=5*2*5*number of cuboids

number of cuboids =5*2*2=20

by the way this subject is math oh and pls mark me as a brainliest

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