please answer me fast
it's urgent
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12
Answer:
Since, Factors of 5 and 2 both are not in group of three. Therefore, the number must be multiplied by2×5×2 = 20 to make it a perfectcube. Hence he needs 20cuboids.
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Answered by
0
Answer:
Here cuboids are joined to form a cube
so,
volume of cuboid* number of cuboid =volume of cube
VOLUME OF CUBOID
sides are 5,2,5 cm
l=5cm
b=2cm
h=5cm
5*2*5
VOLUME OF CUBE
let side of cube =a
volume=side^3
=a^3
now ,
volume of cuboid*number of cuboids =volume of cuboid
5*2*5*number of cuboids=a^3
a^3=5*2*5*number of cuboids
since on the left we have a cube ,
we should have cube on the right as well
to form cube on the right
we multiply
5*2*5
thus in a^3=5*2*5*number of cuboids
number of cuboids =5*2*2=20
by the way this subject is math oh and pls mark me as a brainliest
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