Question

please answer me fast it's urgent ​

Answer 1

Answer:

6

Step-by-step explanation:

using (a+b)(a-b)=a^2-b^2

3^2-3=6

Answer 2

Step-by-step explanation:

Solutions :-

i) Given that :

(3+√3)(2+√2)

=> 3(2+√2) +√3(2+√2)

=> (3×2)+(3×√2)+(√3×2)+(√3×√2)

=> 6+3√2+2√3+√6

(3+√3)(2+√2) = 6+3√2+2√3+√6

ii) Given that

(3+√3)(3-√3)

This is in the form of (a+b)(a-b)

Where a = 3 and b = √3

We know that

(a+b)(a-b) = a²-b²

=> (3+√3)(3-√3)

=> (3)²-(√3)²

=> 9-3

=> 6

(3+√3)(3-√3) = 6

iii) Given that (√5+√2)²

This is in the form of (a+b)²

Where , a = √5 and b =√2

We know that

(a+b)² = a²+2ab+b²

=> (√5+√2)² = (√5)²+2(√5)(√2)+(√2)²

=> (√5+√2)² = 5+2√10+2

=> (√5+√2)² = 7+2√10

(√5+√2)² = 7+2√10

iv) Given that (√5-√2)(√+√2)

This is in the form of (a+b)(a-b)

Where a = √5 and b = √2

We know that

(a+b)(a-b) = a²-b²

=> (√5+√2)(√5-√2)

=> (√5)²-(√2)²

=> 5-2

=> 3

(√5-√2)(√+√2) = 3

Used formulae:-

• (a+b)² = a²+2ab+b²

• (a+b)(a-b) = a²-b²