Question

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Answer 1

Step-by-step explanation:

Given:-

2X^2+9X+4

To find:-

Factorise the given expression by splitting the middle term ?

Solution:-

Given expression is 2X^2+9X+4

It can be written as

=>2 X^2 + X+ 8X + 4

=>X(2X+1) +4(2X+1)

=>(2X+1)(X+4)

therefore, 2X^2+9X+4 = (2X+1)(X+4)

Solution:-

2X^2+9X+4 = (2X+1)(X+4)

Used method:-

Splitting the middle term

• First step :-
• The quadratic pilynomial is ax^2+bx+c
• multiply the coefficient of x^2 and the constant term. = (a×c)
• Second step :-
• Writting the factors of the result.
• Third step:-
• Converting the result like adding or subtracting to get the coefficient of b
• (p+q)=b or (p-q)=b where p×q = a×c.

Answer 2

Answer:

(2x+1)(x+4)

Step-by-step explanation:

given :-

polynomial = 2x²+9x+4

to find -

factors of polynomial by splitting of middle term.

solution :-

2x²+9x+4 =

2x²+x+8x+4 =

x(2x+1)+4(2x+1)= *

(2x+1)(x+4) = **

Hence 2x²+9x+4 = (2x+1)(x+4).

* by taking x common remaining 2x and 1 will be added. Then taking 4 common 2x and 1 will be remaining.

** then taking (2x+1) common x and +4 will be common when we add this we get our factors.

hope it helps.