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Answers
Answer:
[A] Given : Height of the hemispherical dome
is 21 m and it is also the radius of hemisphere.
So Radius of the hemispherical dome is 21 m.
Now, Volume of the hemispherical dome = 2πr³/4
Volume = 2×22×21³/7 = 407484/7
Volume = 58212 m³
[B] The formula to find the volume of a sphere =
4πr³/7
[C] Given the radius of hemispherical dome =
14m
Curved surface area of hemispherical dome =
2πr²
Therefore, C.S.A = 2×22×14²/7 = 1232 m²
Option (b) 1232 m² is the correct answer.
[D] Given the radius of hemispherical dome =
14m
Dimensions of a cuboid = 8m × 6m × 4m
Curved surface area of hemispherical dome =
2πr²
Therefore, C.S.A = 2×22×14²/7 = 1232 m²
Now , Total surface area of cuboid =
2(lb+lh+bh)
T.S.A. = 2[(8)(6)+(8)(4)+(6)(4)]
T.S.A. = 2[48+32+24]
T.S.A. = 2[104] = 208 m²
Since, Hemisphere and cuboid are attached,
so the area of the one face of the cuboid will
subtracted.
Area of one face of the cuboid = lb = 8×6
Area of one face = 48 m²
Therefore, Total Area of the figure = Area of
the hemisphere + area of the cuboid - area of
one face
Total Area of the figure = 1232+208-48 = 1,392
m²
Hence solved.
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