Question

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Answer 1

Answer:

a} Area of the given figure is :77cm²

b} Area of the given figure is :31.5feet²

c} Area of the given figure is :47.5cm²

d} Area of the given Trapezium is :40cm²

Step-by-step explanation:

a} Area of the given figure is :

Area of rect. = 11*4 = 44cm²

Area of triangle = 1/2 * 6 * 11 = 3*11 = 33cm²

Area of the given figure is = 44+33 = 77cm²

b} Area of the given figure is :

Area of rect. = 3*9 = 27feet²

Area of triangle = 1/2 *3 * 3 = 9/2 = 4.5feet²

Area of the given figure is = 27 + 4.5 = 31.5feet²

c} Area of the given figure is :

Area of rect. = 8 * 5 = 40cm²

Area of triangle = 1/2 *3 * 5 = 15/2 = 7.5cm²

Area of the given figure is = 40+7.5 = 47.5cm²

d} Area of the given Trapezium is :

1/2 * Sum of || sides * Perpendicular distance between them

= 1/2 * (13+7) * 4

=2 * 20

Area of the given Trapezium is = 40cm²

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Answer 2

Given:

• Different Trapeziums

Find:

• Area of all Trapezium

Solution:

F1st of all we, have to know area of Trapezium that is

$\large{\underline{\boxed{ \sf Area \: of \: trapezium = \dfrac{1}{2}(a + b)h }}}$

Now,

a)

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(a + b)h$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(4 + 10)11$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(14)11$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2} \times 154$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{154}{2}$

$\dashrightarrow\sf Area \: of \: trapezium = 77 {cm}^{2}$

$\qquad\huge{\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

b)

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(a + b)h$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(9 + 12)3$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(21)3$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2} \times 63$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{63}{2}$

$\dashrightarrow\sf Area \: of \: trapezium = 31.5 \: sq. \: feet$

$\qquad\huge{\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

c)

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(a + b)h$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(11 + 8)5$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(19)5$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2} \times 95$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{95}{2}$

$\dashrightarrow\sf Area \: of \: trapezium = 47.5 {cm}^{2}$

$\qquad\huge{\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

d)

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(a + b)h$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(7 + 13)4$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2}(20)4$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{1}{2} \times 80$

$\dashrightarrow\sf Area \: of \: trapezium = \dfrac{80}{2}$

$\dashrightarrow\sf Area \: of \: trapezium = 40 {cm}^{2}$

$\qquad\huge{\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

Hence,

• Area of 1st Trapezium = 77cm²
• Area of 2nd Trapezium = 31.5 sq. feet
• Area of 3rd Trapezium = 47.5cm²
• Area of 4th Trapezium = 40cm²