Question

please answer me of question number 16

Answer 1

V= 12V
Let r1 r2 and r3 be resistors of 10ohm 3ohm and 6ohm
r2 and r3 are in parallel so
1/Rp = 1/3 + 1/6
Rp = 2 ohms

now, r1 and Rp are in series connections
so, Total resistance of circuit is= 10 +2=12ohms

By ohms law we have
V=IR
I = V/R
I =12/12. (V=12 AND R = 3 OHMS)
I= 1A

Answer 2

I think it's correct