Question

please answer me .please guys​

Answer 1

Step-by-step explanation:

In△BCE

⟹∠BEC+∠BCE+∠CBE=180

∘

⟹90

∘

+30

∘

+∠CBE=180

∘

⟹∠CBE=60

∘

y=60

∘

In△APC:

⟹50

∘

+30

∘

+∠APC=180

∘

⟹∠APC=100

∘

∴x=180−∠APC

(∵sumofanglesonastraightline=180

∘

)

⟹x=180

∘

−100

∘

=80

∘

In△BOP:

z=x+y(exteriorangleofatriangle=sumoftwooppositeinteriorangles)

⟹z=80+60=140

∘

∴x=80

∘

,y=60

∘

,z=140

∘

Answer 2

Answer:

x=80. y=25. z=140.

Step-by-step explanation:

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