Question

please answer me question number 22 it's urgent guys??

Answer 1

Hola User__________________

Here is Your Answer...!!!
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↪⭐Actually welcome to the concept of the Areas related to The circles

↪Basically here we have to calculate the Area of the given figure ...

↪so we have to first calculate the area of the biggest semi circle ..

↪after that we have to calculate the area of the medium semi circle and subtract it from The biggest semi circle

↪at last we have calculate the area of the smallest semi circle and add it to the total area above
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Answer 2

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Given,
PQRS is a diameter of a circle of Radius 6 cm
$PS = 2×6 = 12\: cm$

And the Lengths of PQ , QR & RS are equal
As PS is divided into 3 equal parts

$PQ + QR + RS = 3 × PS$
=> $PQ = QR = RS = \frac{1}{3}PS$
=> $PQ = \frac{12}{3} = 4\: cm$

$QS = PQ + PQ$
=> $QS = 4 + 4 = 8\: cm$


Here,
To find Area of dotted region , the below has to be found:

- Area of semicircle(with PS as diameter)
= $\frac{1}{2} × {\pi×6^{2}}$
{d = PS = 12 => r = 6}
= $18\pi$

- Area of Semicircle (with QS as diameter)
= $\frac{1}{2} ×{\pi×4^{2}}$
{d = QS = 8 => r = 4}
= $8\pi$

- Area of Semicircle( with PQ as diameter)
$\frac{1}{2} ×{\pi×2^{2}}$
{d = QS = 4 => r = 2}
= $2\pi$


Now,
Required Area of dotted Region =
Area of semicircle(with PS as diameter) - Area of Semicircle (with QS as diameter) + Area of Semicircle( with PQ as diameter)

=> Required Area = $18\pi$ - $8\pi$ + $2\pi$
= $12\pi$
= 37.68 cm².



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