please answer me questions no 17 both are important ??
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hey mate here is your answer ✌♥
Given ΔABC and ΔDBC are on the same BC. AD and BC intersect at O.
Prove that :ArΔABC/ArΔDBC=AO/DO
AL⊥BCandDM⊥BC
Now, in ΔALO and ΔALO we have
∠ALO = ∠DMO =90∘
∠AOL =∠DOM (vertically opposite angles)
Therefore ΔALO∼ΔDMO
∴ AL/DM=AO/DO
ArΔABC/ArΔBCD=(1/2×BC×AL)/(1/2×BC×DM)
=AL/DM
=AO/DO
hope it will help you♥♥
mark me brainliest ✌✌
Given ΔABC and ΔDBC are on the same BC. AD and BC intersect at O.
Prove that :ArΔABC/ArΔDBC=AO/DO
AL⊥BCandDM⊥BC
Now, in ΔALO and ΔALO we have
∠ALO = ∠DMO =90∘
∠AOL =∠DOM (vertically opposite angles)
Therefore ΔALO∼ΔDMO
∴ AL/DM=AO/DO
ArΔABC/ArΔBCD=(1/2×BC×AL)/(1/2×BC×DM)
=AL/DM
=AO/DO
hope it will help you♥♥
mark me brainliest ✌✌
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