Please answer my 18th and 19th question
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Question 19
We know that sum of opposite angle of cyclic quadrilateral= 180
So A+C=180
4y+20+4x=180
4(x+y)=180-20
x+y= 40 ..........(1)
and B+D=180
2y-5+6x+5=180
2(3x+y)=180
3x+y=90 ........... (2)
now subtract (1)from(2) we get,
2x=50
So x=25
and x+y=40
25+y=40
y=40-25
=15
We know that sum of opposite angle of cyclic quadrilateral= 180
So A+C=180
4y+20+4x=180
4(x+y)=180-20
x+y= 40 ..........(1)
and B+D=180
2y-5+6x+5=180
2(3x+y)=180
3x+y=90 ........... (2)
now subtract (1)from(2) we get,
2x=50
So x=25
and x+y=40
25+y=40
y=40-25
=15
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