Question

please answer my physics question take ur time but answer correctly pls ☺☺​

Answer 1

1. One ohm is defined as the resistance offered by the conductor when one ampere of current flows through the conductor with a potential difference of one volt.

According to ohm's law, V = IR

R = V/I

2.Potential difference, V = 12 volt

Current, I = 5A

V = IR

R = V/I

$= \frac{12}{5} \\ \\ = 2.4 \: ohm$

Resistance offered is 2.4 ohm

3. Resistance,R = 6 ohm

Current, I = 2.4 A

V = IR

V = 2.4 × 6

V = 14.4 volt

Potential difference is 14.4 volt

4. Resistance ,R = 4 ohm

Potential difference, V = 4 volt

V = IR

I = V/ R

I = 4/4

I = 1 ampere

Current flowing is 1 A

5.Resistance ,R = 12 ohm

Potential difference, V = 18 volt

V = IR

I = V/ R

I = 18/12 = 6/4 = 3/2 = 1.5

I = 1.5 ampere

Current flowing is 1.5 A

6. Potential difference V = 20 volt

Current ,I = 3 A

Resistance ,R = 4 ohm

Potential difference, V = 4 volt

V = IR

R = V/ I

= 20 /3

R = 6.67 ohm

If 30 volt is applied across the same resistor,

Resistance, R = 6.67 = 20/3 ohm

Potential difference, V = 30 volt

V = IR

I = V/ R

$= \dfrac{30}{ (\frac{20}{3} )} \\ \\ = \dfrac{30 \times 3}{20} \\ \\ = \dfrac{3 \times 3}{2} \\ \\ = \frac{9}{2} \\ \\ = 4.5 \: ampere$

Current is 4.5 A

7.Potential difference, V = 2 volt

Resistance, R = 1 ohm

Time, t = 2 minutes

t = 2 × 60 seconds

t = 120 seconds

V = IR

I = V/R

= 2/1

I = 1 ampere

Let q be the charge of electrons

Let n be the number of electrons

I = q/t

q = I × t

$q= 1 \times 120 \\ \\ q = 120 \: coulomb$

We know that, q = ne, where e is the charge of electron.

e = 1.6 × 10^-19 coulomb

$q = ne \\ \\ n = \frac{q}{e} \\ \\ n = \dfrac{120}{1.6 \times {10}^{ - 19} } \\ \\ n = \dfrac{120 \times {10}^{19} }{1.6} \\ \\ n = 75 \times {10}^{19} \: electrons$

The number of electrons coming out is 75× 10¹⁹ electrons.

8.Potential difference, V = 20 volt

Current, I = 0.4 A

V = IR

R = V/I

= 20/0.4

= 200/4

R = 50 ohm

Resistance is 50 ohm.

When it is connected to 6 volt, let the current bt I'

Resistance, R = 50 ohm

Potential difference, V = 6 volt

V = IR

I = V/R

= 6/50

I = 0.12 ampere

Current is 0.12 A

9. Refer to the attachment

To find R consider a single set of value.

Let's consider the first set.

Current in ammeter, I = 100 mA

Potential difference in voltmeter, V = 2 mV

V = IR

R = V/I

= 2/100

R = 0.02 ohm

Resistance is 0.02 ohm.