please answer my question
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Step-by-step explanation:
Given: θ = 30°.
(i)
cos 3θ = 4 cos³θ - 3 cosθ
⇒ cos 3(30°) = 4 cos³(30) - 3 cos(30°)
⇒ cos 90° = 4 (3√3/8) - 3(√3/2)
⇒ cos 90° = (3√3/2) - (3√3/2)
⇒ 0 = 0.
(ii)
Given: sin 3θ = 3 sinθ - 4 sin³θ
⇒ sin 3(30°) = 3 sin(30°) - 4 sin³(30°)
⇒ sin 90° = 3(1/2) - 4(1/8)
⇒ 1 = (3/2) - (1/2)
⇒ 1 = 2/2
⇒ 1 = 1
Hope it helps!
avni6279:
thanks
Answered by
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cos 3θ = 4 cos³θ - 3 cosθ
cos 3(30°) = 4 cos³(30) - 3 cos(30°)
cos 90° = 4 (3√3/8) - 3(√3/2)
cos 90° = (3√3/2) - (3√3/2)
0 = 0.
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