Question

please answer my question​

Answer 1

Answer:

FC = FE + DE + DC

In BCD

sin 60 = P/ H

√3/2=DC/12

6√3= DC

10.4 = DC

cos 60 = B/ H

1/2 = B/12

12/2 = BD

6 = BD

BD = AE

AE = 6

In AEF

Tan 45 = P/ B

1 = 6/FE

FE = 6

so, FC = 10.4 + 6 + 7

FC = 23.4 ( answer)

Answer 2

Answer:

23.4 is value of fc......

acc to me