Question

please answer my question​

Answer 1

Answer:

The sum of the areas of the exposed top surfaces of the two smaller cubes equals the covered

area of the top surface of the largest cube.

So the total horizontal area to be painted is 3 × 3 = 9 m .

2

Total area of the vertical surfaces is 4 × (3 × 3 + 2 × 2 + 1 × 1) = 56 m .

2

So the total area is 9 + 56 = 65 m .

2

Hence 7 tins of paint needed (with a half tin left over).

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