Math, asked by raywi5272991, 7 months ago

please answer my question​

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Answers

Answered by routaishwarya1
1

Step-by-step explanation:

Principal (P) = Rs. 640

Amount (A) = Rs. 774.40

Time (n) = 2 years

Rate of interest (R) % = ?

We know that,

\begin{gathered}A = P {(1 + \frac{R}{100} )}^{n} \\ \\ 774.40 = 640 {(1 + \frac{R}{100} )}^{2} \\ \\ 774.40 = 640 {(1 + \frac{R}{100} )}^{2} \\ \\ \frac{774.40}{640} = {(1 + \frac{R}{100} )}^{2} \\ \\ \frac{77440}{640 \times 100} = {(1 + \frac{R}{100} )}^{2} \\ \\ \frac{121}{100} = {(1 + \frac{R}{100} )}^{2} \\ \\ { (\frac{11}{10}) }^{2} = {(1 + \frac{R}{100} )}^{2} \\ \\ \frac{11}{10} = 1 + \frac{r}{100} \\ \\ \frac{11}{10} - 1 = \frac{R}{100 } \\ \\ \frac{11 - 10}{10} = \frac{r}{100} \\ \\ \frac{1}{10 } = \frac{R}{100} \\ \\ \frac{1}{10} \times 100 = r \\ \\ 10 = R\end{gathered}

A=P(1+

100

R

)

n

774.40=640(1+

100

R

)

2

774.40=640(1+

100

R

)

2

640

774.40

=(1+

100

R

)

2

640×100

77440

=(1+

100

R

)

2

100

121

=(1+

100

R

)

2

(

10

11

)

2

=(1+

100

R

)

2

10

11

=1+

100

r

10

11

−1=

100

R

10

11−10

=

100

r

10

1

=

100

R

10

1

×100=r

10=R


raywi5272991: thanks
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