please answer my question
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depressedgirl:
what is its answer
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Here is your solution
Given:-
PQ is a chord of a circle with center O.
∠QPT = 60°
Let x be the point on the tangent PT.
Now
∠QPT + ∠QPX = 180° [Linear pair]
=>∠QPX= 180° - ∠QPT
=>∠QPX= 180° - 60° = 120°
=>∠QPX=120°
∠QPX = ∠PRQ [Alternate segment theorem]
Hence
∠PRQ = 120°
hope it helps you
Given:-
PQ is a chord of a circle with center O.
∠QPT = 60°
Let x be the point on the tangent PT.
Now
∠QPT + ∠QPX = 180° [Linear pair]
=>∠QPX= 180° - ∠QPT
=>∠QPX= 180° - 60° = 120°
=>∠QPX=120°
∠QPX = ∠PRQ [Alternate segment theorem]
Hence
∠PRQ = 120°
hope it helps you
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