please answer my question
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if the points are equidistant
we can say that
distance from (x,y) to (t+1,1-t) is equal to distance b/w (x,y) and (t-1,1+t)
distance formula
√(x-t-1)²+(y-1+t)²=√(x-t+1)²+(y-1-t)²
x²+t²+1+2t-2xt-2x+y²+1+t²-2t-2y+2yt=x²+t²+1-2t-2xt+2x+y²+t²+1+2t-2yt-2y
1+2x+1-2yt=1-2x+1+2yt
2x-2yt=2yt-2x
4x=4yt
x=yt
we can say that
distance from (x,y) to (t+1,1-t) is equal to distance b/w (x,y) and (t-1,1+t)
distance formula
√(x-t-1)²+(y-1+t)²=√(x-t+1)²+(y-1-t)²
x²+t²+1+2t-2xt-2x+y²+1+t²-2t-2y+2yt=x²+t²+1-2t-2xt+2x+y²+t²+1+2t-2yt-2y
1+2x+1-2yt=1-2x+1+2yt
2x-2yt=2yt-2x
4x=4yt
x=yt
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