Please answer my question
Answers
Hey there!
For your question, let's assume there are "x" number of 50 p coins and "y" number of 25 p coins.
Hence,
x + y = 76x+y=76
Thus Total Money =
0.5x + 0.25y0.5x+0.25y
Since 50p = Rs 0.5 and 25p = Rs 0.25
But we have been given that the total money Alima has is Rs 29. Hence:
\begin{lgathered}0.5x + 0.25y = 29 \\ \frac{x}{2} + \frac{y}{4} = 29 \\ \frac{1}{4}(2x + y) = 29 \\2x + y = 116 \\ x + ( x+ y) = 116\end{lgathered}
0.5x+0.25y=29
2
x
+
4
y
=29
4
1
(2x+y)=29
2x+y=116
x+(x+y)=116
Here we know that (X + Y) is equal to 76, from the above equation, so we substitute it in this equation.
\begin{lgathered}x + 76 = 116\\ x = 116 - 76 \\ x = 40\end{lgathered}
x+76=116
x=116−76
x=40
Now we find the value of Y, using the first equation:
\begin{lgathered}x + y = 76 \\ 40 + y = 76 \\ y = 76 - 40 \\ y = 36\end{lgathered}
x+y=76
40+y=76
y=76−40
y=36
Hence X = 40 and Y = 36.
Thus Alima has forty 50p coins and thirty-six 25p coins.