Please answer my question in the atttachment
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Answered by
5
hey ...here is your answer...❤️
area of shaded region:- area of circle-area of square.
given diagonal=2r
and
we know that, diagonal=√2*side
2r=√2*side
side=2r/√2
side=√2r........................................................()
shaded region= πR²-(ST)²
=πr²-(√2r)²
=πr²-2r²
=r²(π-2)____.____.____.____answer
hence, option (a) is correct.
don't forget to mark as brainleist.
area of shaded region:- area of circle-area of square.
given diagonal=2r
and
we know that, diagonal=√2*side
2r=√2*side
side=2r/√2
side=√2r........................................................()
shaded region= πR²-(ST)²
=πr²-(√2r)²
=πr²-2r²
=r²(π-2)____.____.____.____answer
hence, option (a) is correct.
don't forget to mark as brainleist.
Answered by
4
(A) r² ( π - 2
Diagonal = √2*side
So,we have to find the area of shaded portion.
So,For it we have to subtract the area of circle with area of square.
Here,
Area of circle = π r²
Area of square = a²
Hey,side of sqaure is not given . So, what happened ?
We have our 20th century brain we can find it in one whistle . isn't it ?
So,
Hey,wait sometimes ago we talked about the relation between side and sqaure .
I hope may you remember that is -
Diagonal = √2 * side
If you didn't remember then go and have some nuts now !
So,
We know , diagonal = 2r [I hope you know]
2r = √2*side
side = 2r/√2
side = √2r
So,(finally) area of sqaure = a²
= (√2r)²
= 2 r²
So,
Subtracting area of circle with area of square
Area of circle - Area of square
πr² - 2 r²
Taking r² common
r²(π - 2)
So,
r²(π - 2) is correct and is your answer.
❤I HOPE MAY IT HELPS YOU ❤
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Anonymous:
nice !
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