Question

please answer my question....it's really urjent​

Answer 1

Hope your doubt is clear.

Answer 2

Solution :-

we know that,

• A quadratic equation with sum and product of roots can be written as :- x² - (sum of zeros)x + product of zeros = 0 .

given that,

• zeroes of the polynomial are = ɑ and 1/ɑ .

so,

• sum of zeros = (ɑ + 1/ɑ) = {(ɑ² + 1) / ɑ} .
• product of zeros = ɑ * 1/ɑ = 1 .

then,

→ ax² + bx + c = x² - (sum of zeros)x + product of zeros .

→ ax² + bx + c = x² - {(ɑ² + 1) / ɑ}x + 1

comparing we get,

• a = 1
• b = (-ɑ² - 1) / ɑ
• c = 1 .

hence, value of b is (-ɑ² - 1) / ɑ .

Learn more :-

x²–8x+2=0 या वर्गसमीकरणाच्या मुळांची बेरीज ककिती

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