Math, asked by hansy12, 1 year ago

Please answer my question it's urgent​

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Answers

Answered by dk6060805
1

Answer is ONE

Step-by-step explanation:

As per the given question we have --

= x^3^a^+^3^b\times x^3^b^+^3^c \times x^3^c^+^3^a / x^6^a \times x^6^b \times x^6^c

= x^3^a\times x^3^b \times x^3^b \times x^3^c\times x^3^a \times x^3^c / x^6^a \times x^6^b \times x^6^c

= x^3^a^+^3^a\times x^3^b^+^3^b \times x^3^c^+^3^c / x^6^a \times x^6^b \times x^6^c

= x^6^a \times x^6^b \times x^6^c / x^6^a \times x^6^b \times x^6^c

= 1

Answer is ONE

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