please Answer my question please
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refer to the attached image for explanation.......
Step-by-step explanation:
Hope it will help you!!! Kindly mark my Answer as Brainliest......
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Step-by-step explanation:
Given:- ∠B < ∠A and ∠C < ∠D
To prove:- AD < BC
Proof:-
In ΔAOB,
∠B < ∠A
= AO < BO [Side opposite to the greater angle is longer.]
= AO < BO ------ 1
In ΔCOD,
∠C < ∠D
= OD < OC [Side opposite to the greater angle is longer.]
= OD < OC ------ 2
Thus, Adding eq.1 and eq.2 we get,
AO + OD < BO + OC
= AD < BC
Because, AD = AO + OD and BC = BO + OC
Hope it helped and you understood it........All the best
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