Please answer my question with solution.
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Answered by
2
Here is your answer–
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
Total number of Bag B in Bag A–› (n-1)
☆Because on Of the bag B is removed.
Total no. of Bag C in Bag B is –› n
No. of coins in Bag C–› n
so
![the \: total \: no. \: of \: coins \: in \: bag \: a \: is - (n - 1) \times n \times n \\ = {n}^{2} (n - 1) the \: total \: no. \: of \: coins \: in \: bag \: a \: is - (n - 1) \times n \times n \\ = {n}^{2} (n - 1)](https://tex.z-dn.net/?f=the+%5C%3A+total+%5C%3A+no.+%5C%3A+of+%5C%3A+coins+%5C%3A+in+%5C%3A+bag+%5C%3A+a+%5C%3A+is+-+%28n+-+1%29+%5Ctimes+n+%5Ctimes+n+%5C%5C++%3D++%7Bn%7D%5E%7B2%7D+%28n+-+1%29)
Hope it will help you!!!
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
Total number of Bag B in Bag A–› (n-1)
☆Because on Of the bag B is removed.
Total no. of Bag C in Bag B is –› n
No. of coins in Bag C–› n
so
Hope it will help you!!!
Answered by
1
Hope it helps
It’s a nice Q
If you got helped then PLZZ help back marking brainliest :))
It’s a nice Q
If you got helped then PLZZ help back marking brainliest :))
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taruntalan314:
Thanks for explaining.
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