Question

please answer my questions please​

Answer 1

let the 4 consecutive no.s be,

a-d, a, a+d, a+2d

sum = 4a+2d =32

2a+d=32/2 =16

u1u4 :u2u3 =7:15

a²+ad-2d² : a²+ad =7:15

substract 1 on both sides

-2d²/a²+ad = -8/15

15d² =4a²+4ad

4a²+4ad -15d² =0

4a²+10ad-6ad-15d² =0

2a(2a+5d)-3d(2a+5d) =0

a =3d/2, -5d/2

4d =16, d=4 => a=6

no are 2, 6, 10, 14

-4d=16, d=-4 => a=10

no are 14, 10, 6, 2

so 4 consecutive no.s are 2,6,10,14