Question

please answer only if you know​

Answer 1

Answer:

secx=2

We know, sec

3

π

=2 and sec

3

5π

=sec(2π−

3

π

)=sec

3

π

=2.

Therefore, the principal solutions are x=

3

π

and

3

5π

.

Now, secx=sec

3

π

cosx=cos

3

π

x=2nπ±

3

π

, where n∈Z.

Therefore, the general solution is x=2nπ±

3

π

,n∈Z.

Step-by-step explanation:

I hope this helped mark me as Brainlist