Math, asked by jejurejyoti, 8 months ago

please answer please answer​

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Answered by mustaphaismail304
1

Answer:

Step-by-step explanation:

to simplify \sqrt{27},   \sqrt{50},  \sqrt{250}

let start with \sqrt{27}

\sqrt{27} = \sqrt{9 x 3}

using law of surd

\sqrt{9 x 3} = \sqrt{9} x \sqrt{3}

= 3\sqrt{3}

for \sqrt{50}

\sqrt{50} = \sqrt{25 x 2}

using law of surd

\sqrt{25 x 2} = \sqrt{25} x \sqrt{2}

= 5\sqrt{2}

for \sqrt{250}

\sqrt{250} = \sqrt{25 x 10}

using law of surd

\sqrt{25 x 10} = \sqrt{25} x \sqrt{10}

= 5\sqrt{10}

in summery  \sqrt{27} =3 \sqrt{3},      \sqrt{50} = 5\sqrt{2},    \sqrt{250} = 5\sqrt{10}

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