using factor method divide (x+3)(x^2-5x+6) by x^2-9
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x - 2
Step-by-step explanation:
Dividend = (x + 3)(x² - 5x + 6)
x² - 5x + 6 = x² - 2x - 3x + 6
= x(x - 2) - 3(x - 2)
= (x - 2)(x - 3)
Divisor = x² - 9
By applying the property a² - b² = (a + b)(a - b)
Divisor = (x + 3)(x - 3)
Dividing the dividend with the divisor =>
[ (x + 3)(x - 2)(x - 3) ]
= -----------------------------
[ (x + 3)(x - 3) ]
(x - 3)(x + 3) will get cut
= x - 2
Hope this helps! :D
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Divide: (x+3) (x^2-5x+6) by x^ 2-9 - 9166312. ... (x + 3)(x - 3). Dividing the dividend with the divisor =>. [ (x + 3)(x - 2)(x - 3 ) ].
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