Math, asked by ajaimkumar06, 11 months ago

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Answered by amitkumar44481
1

 \tt{Let's \:  find  \: out  \:  \red{How}  \: ?} \\  \\

 \tt{We  \: have  \:  \underline{given}  \: value \:  of  \:  \red{x}.} \\

 \:  \:  \:  \:  \:  \:  \tt{x =  \sqrt{30 -  \sqrt{30 -  \sqrt{30......} } } }

 \tt{Squaring \:  both  \: sides, we  \: get.}

 \:  \:  \:  \:  \:  \:  \tt{ {x}^{2}  = 30 - x.}

 \:  \:  \:  \:  \:  \:   \tt{{x}^{2}  + x - 30 = 0.}

 \:  \:  \:  \:  \:  \:   \tt{{x}^{2}  + 6x  - 5x - 30 = 0.}

 \:  \:  \:  \:  \:  \:   \tt{x(x + 6) - 5(x +  6) = 0.}

 \:  \:  \:  \:  \:  \:   \tt{(x + 6)(x - 5) = 0.}

 \tt{Therefore, the \:  value \:  of }

 \:  \:  \:  \:  \:  \:  \:  \:  \:    \huge \tt{c) \:  \:  \: {x }^{2} = 25.}

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Answered by brainyboy88
3
Pl pl mark me brainliest bro
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