Question

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Answer 1

➠ Questíon :-

➝ An electric iron of resistance 20ᘯ takes a current of 5A. Calculate the heat developed in 30s.

➠ Gíven :-

➝ Current, I = 5A

➝ Resistance, R = 20ᘯ

➝ Time, t = 30s

➠ To fínd :-

➝ The heat developed in 30s

➠ Formula requíred :-

$\longrightarrow \boxed{\sf H = I²×R×T}$

➠ Solutíon :-

$\longrightarrow \tt h = {(5)}^{2} \times 20 \times 30$

$\longrightarrow \tt h = 25 \times 20 \times 30$

$\longrightarrow \tt h = 15000j$

Thus, the heat developed in 30s is 15000joules.

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Additional information.......

➤ What is heat ?

• heat is a form of energy that causes a difference in temperature, or the perception of warmth. An example of heat is hot water.

⋆ SI unit of Heat is : Joules

➤ What is current ?

• An electric current is a flow of electric charge in a circuit. More specifically, the electric current is the rate of charge flow past a given point in an electric circuit.

⋆ SI unit of current is : Ampere

➤ What is Resistance ?

• Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).

⋆ SI unit of resistance is : ohms