Physics, asked by john44, 1 year ago

please answer q. 11 with figure please!!!!!!

Attachments:

Answers

Answered by abhi178
1
uniform velocity :- it means acceleration = 0
it means
velocity is constant .
hence,
when body starts to go and reach the wall , covered distance is S and displacement is D

S = vt = 10 × 6 = 60 m
D = 10 × 6 = 60m

now after striking body moves backward with same speed and reach initial point then displacement D' and and distance S'.
[ direction is changed( just opposite direction ) so, velocity sign changed e.g V = -10m/s

D' = -10 × 6 = - 60m
S' = | D' | = 60m

now ,
total distance = S + S' = 60 + 60 = 120m
total displacement = D+ D' = 60 - 60 = 0
Attachments:

john44: thanks alot
sandhyabehera: from which book u r asking the que?
john44: don't bother it
Answered by erajireddy6
0

Answer:

uniform velocity :- it means acceleration =

it means

velocity is constant

.

hence,

when body starts to go and reach the wall, covered distance is S and displacement is D

S = vt = 10 x 6 = 60 m D = 10 x 6 = 60m

now after striking body moves backward with same speed and reach initial point then displacement D' and and distance S.

[ direction is changed( just opposite direction ) so, velocity sign changed e.g V = -10m/s

D' = -10 6 = -60m S' = I D'| = 60m

now,

total distance = S+ S' = 60 + 60 = 120m = total displacement = D+ D' = 60 - 60 = 0

Attachments:
Similar questions