Math, asked by john44, 1 year ago

please answer Q10.......

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Answered by prajapatyk
0
let A={1,2,3,4,5,6}...........................1
B={2,4,6}.....................................2
C={2,4,6,8}..................................3
AΠB={1,2,3,4,5,6}Π{2,4,6}
AΠB={2,4,6}......................................4
AΠC={1,2,3,4,5,6}Π{2,4,6,8}
AΠC={2,4,6}.......................................5
By eq4 and eq5 we get
AΠB=AΠC
But ,by eq2 and eq3 it is clear that,
B≠C
Hence,AΠB=AΠC need not imply B=C




In the case of B=C, the above statement i.e AΠB=AΠC still remains same.It only means that in the case AΠB=AΠC , B=C is not important.In the case AΠB=AΠC they may be equal or they may not be equal.But surely one of them will be subset of other i.e in sets of B and C.

john44: please can u tell can we choose any set randomly
prajapatyk: yes
prajapatyk: but while choosing sets we should be carefull about what we need to show
prajapatyk: the given statement with given condition
john44: oh thanks alot please can you answer my other question s please
prajapatyk: how can i search for those questions
john44: you can see in my profile in that my question s there u ill finf it
prajapatyk: ok i will try if i can
john44: ok thanks
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