please answer Q4 and Q5( i want explanation!!!!!!! dont give direct answer
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4) you see graph , here maximum change in velocity in time interval 3 < t < 5.
so, maximum acceleration = change in velocity /time interval
= ( -6 -6)/2 = -6 m/s²
so, magnitude of acceleration = 6 m/s²
5) car first moves in North direction with speed 20 . and then moves East direction.
so, Vi = 20j
Vf = 20i
so, change in velocity = final - initial
= 20i -20j
= 20( i - j )
magnitude = √(20² +20²) = 20√2 m/s
here you see x → ( +ve)
y → ( -ve) which quadrant x is positive and y is negative .??
off course 4th quadrant so,
direction of change in velocity is East - South or south- East
so, maximum acceleration = change in velocity /time interval
= ( -6 -6)/2 = -6 m/s²
so, magnitude of acceleration = 6 m/s²
5) car first moves in North direction with speed 20 . and then moves East direction.
so, Vi = 20j
Vf = 20i
so, change in velocity = final - initial
= 20i -20j
= 20( i - j )
magnitude = √(20² +20²) = 20√2 m/s
here you see x → ( +ve)
y → ( -ve) which quadrant x is positive and y is negative .??
off course 4th quadrant so,
direction of change in velocity is East - South or south- East
abhi178:
see the answer john i hope this is correct
absolutely correct but what is this i and j
i is unit vector along x-axis and j is unit vector along y-axis
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I hope it will help u.....
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thanks alot but what is i and j
its a unit vector along x axis and y axis
oh thanks
but unit vector = 1 then what is use of writing it?
unit vectors shows direction....
if you miss i^ ,j^ and k^ then your answer will be wrong..... vector itself means the one with magnitude and direction
dear @john magnitude of unit vector is 1 not unit vector = 1 ...unit vector only shows of direction of vector quantity...
oh thanks
like F = 2 i means force is 2 newton acting along positive x direction
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