Math, asked by john44, 1 year ago

please answer Q4 and Q5( i want explanation!!!!!!! dont give direct answer

Attachments:

Answers

Answered by abhi178

4) you see graph , here maximum change in velocity in time interval 3 < t < 5.

so, maximum acceleration = change in velocity /time interval
= ( -6 -6)/2 = -6 m/s²

so, magnitude of acceleration = 6 m/s²

5) car first moves in North direction with speed 20 . and then moves East direction.
so, Vi = 20j
Vf = 20i

so, change in velocity = final - initial
= 20i -20j

= 20( i - j )

magnitude = √(20² +20²) = 20√2 m/s

here you see x → ( +ve)
y → ( -ve) which quadrant x is positive and y is negative .??
off course 4th quadrant so,
direction of change in velocity is East - South or south- East

abhi178: see the answer john i hope this is correct

john44: absolutely correct but what is this i and j

Anonymous: i is unit vector along x-axis and j is unit vector along y-axis

Answered by Anonymous

I hope it will help u.....

Attachments:

john44: thanks alot but what is i and j

Anonymous: its a unit vector along x axis and y axis

john44: oh thanks

john44: but unit vector = 1 then what is use of writing it?

Anonymous: unit vectors shows direction....

Anonymous: if you miss i^ ,j^ and k^ then your answer will be wrong..... vector itself means the one with magnitude and direction

Anonymous: dear @john magnitude of unit vector is 1 not unit vector = 1 ...unit vector only shows of direction of vector quantity...

john44: oh thanks

Anonymous: like F = 2 i means force is 2 newton acting along positive x direction

Previous Question

Next Question