Question

Please answer ques. 3​

Answer 1

$let \: \alpha = \sqrt{ \frac{5}{3} } \\ let \: \beta = - \sqrt{ \frac {5}{3} } \\ \alpha + \beta = \sqrt{ \frac{5}{3} } + ( - \sqrt{ \frac{5}{3} } ) \\ \alpha + \beta = 0 \\ \alpha \beta = \sqrt{ \frac{5}{3} } \times - \sqrt{ \frac{5}{3 } } \\ \alpha \beta = \frac{ - 5}{3}$

The formula of quadratic equation is

${x}^{2} - ( \alpha + \beta ) + \alpha \beta \\ {x}^{2} - 0 - \frac{5}{3} \\ 3 {x}^{2} - 5$

So 3x^2-5is a factor of given equation

Now divide 3x^2-5 with given equation

And factorize the quotient

To get the zeroes