Question

Please answer question 1 ,2 and 3 with proper explanation

Answer 1

1. let the number of prizes of $100 = x
and of $25 = y

so
=> x+y = 63
=> 100x + 25y = 2700
4x + y = 108
____________
3x = 45
x = 15
y = 48

so prizes of $100 = 15
and $25 = 48


2. let the boys = b
and girls = g

so
=> g+b = 60
and
b = 2/5g

=> (2/5+1)g = 60
g = 60×5÷7

"i think question is wrong"


3. let the angles are A and B
so
A+B = 180
|A-B| = 36
2A = 216
so
A = 108°
B = 72°



hope it helps you
@di

Answer 2

(1)

Let the number of prizes worth 100$ = x.

Let the number of prizes worth 25$ = y.

Given : x + y = 63.  ------ (1)

Given : 100x + 25y = 2700

             4x + y =  108 ---- (2)

Multiply (1) *4, We get

= > 4x + 4y = 252

     4x + y = 108

    -------------------------

             3y = 144

              y = 48.


Substitute y = 48 in (1), we get

= > x + y = 63

= > x + 48 = 63

= > x = 63 - 48

= > x = 15.


Therefore the number of prizes worth 100$ = 15 and worth 25$ = 48.



(2)

Let the number of girls in the class be x.

Given that boys is 2/5 of the girls = 2/5 * x

                                                         = 2x/5



Given that total number of students in the class = 60.

= > x + 2x/5 = 60

= > 7x/5 = 60

= > 7x = 60 * 5

= > 7x = 300

= > x = 300/7.


Your question seems to be wrong.



(3)

Let the measure of the supplementary be x.

Then the other one will be 36 + x.

We know that supplementary angles add up to 180.

= > x + 36 + x = 180

= > 2x + 36 = 180

= > 2x = 180 - 36

= > 2x = 144

= > x = 72.

If one angle is 72, then the other one will be 72 + 36 = 108.


Therefore the measures are 72 and 108.


Hope this helps!