Question

please answer question 6 and 9

Answer 1

8.

S-t=3..................01
s/3+t/2=6...........02
Solve by substitution method


Eq no. 2

S-t=3
S=3+t..................03

Put the value of S in Eq 1

S/3+t/2=6
3+t/3+t/2=6

LCM of 3 and 2=6

2(3+t)+3(t)/6=6

Cross multiply

6+2t+3t=6×6

5t+6=36
5t= 36-6
t=30/5=6

Put the value of t in eq 3

S=3+t
S=3+6=9