Question

Please Answer Question Number 6​

Answer 1

Step-by-step explanation:

given AB=a

BC=a

AC=√a²+a²

AC=√2 a

(i)sinA=BC/AC

=a/√2 a

=1/√2

(ii)secA=AC/AB

=√2a/a

=√2

(iii)cos²A+sin²A

=(AB/AC)²+(1/√2)²

=(1/√2)²+(1/√2)²

=1/2+1/2

=1+1/2

=1