Question

Please answer questions number 5

Answer 1

given
FD = BE
AE = DC
angleDFC = angleEBA

TO PROVE
AB = FC
AF = BC

PROOF
In ∆ABE and ∆CFD
ANG DFC = ANG EBA
FD =BE
AE = DC
∆ABE~= ∆CFD

AB=FC (CPCT)


AF+FB=FB+BC (AB=FC)
AF=BC [FB=FB(Common)]
AF=BC
proved